medium4 marks

Concrete Structures

5 Topics

25h prep

25% subject weight

5 Topics

1

Design of beams

1m4/10

📌 Key FormulaMu = 0.138 fck b d² (balanced)

2

Design of slabs

1m4/10

📌 Key FormulaOne-way vs two-way coefficients

3

Design of columns

1m4/10

📌 Key FormulaPu = 0.4 fck Ac + 0.67 fy Asc (short)

4

Bond and development length

1m3/10

📌 Key FormulaLd = (φ σ_s)/(4 τ_bd)

5

Prestressed concrete beams

1m4/10

📌 Key FormulaLosses in prestress

medium4 marks

Concrete Structures

5 Topics

25h prep

25% subject weight

5 Topics

1

Design of beams

1m4/10

📌 Key FormulaMu = 0.138 fck b d² (balanced)

2

Design of slabs

1m4/10

📌 Key FormulaOne-way vs two-way coefficients

3

Design of columns

1m4/10

📌 Key FormulaPu = 0.4 fck Ac + 0.67 fy Asc (short)

4

Bond and development length

1m3/10

📌 Key FormulaLd = (φ σ_s)/(4 τ_bd)

5

Prestressed concrete beams

1m4/10

📌 Key FormulaLosses in prestress